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Semmy [17]
3 years ago
11

If i = V-1, then (3 – i)(3+ i) =

Mathematics
1 answer:
castortr0y [4]3 years ago
4 0
9-i^2
9-v^+2v-1
-v^2 +2v +8
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PLEASE HELP!
Oksana_A [137]

Answer:

c) A rectangle with width of 9 mm and length of 45 cm.

d) A rectangle with width of 10 cm and length of 44 cm.

Step-by-step explanation:

Given:

Length of the rectangle = 32 in.

Width of the rectangle = 8 in.

First we will find the ratio of length by width.

\frac{length}{width}= \frac{32}{8} = \frac{4}{1} \ \ \ \ equation \ 1

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

a) A rectangle with width of 23 cm and length of 92 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{92}{23} = \frac{4}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 = equation 2

Hence This rectangle is similar to Carl's rectangle.

b) A rectangle with width of 2.5 inch and length of 10 inch.

we will find the ratio of length by width.

\frac{length}{width}= \frac{10}{2.5} = \frac{4}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 = equation 2

Hence This rectangle is similar to Carl's rectangle.

c) A rectangle with width of 9 mm and length of 45 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{45}{9} = \frac{5}{1} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 \neq equation 2

Hence This rectangle is not similar to Carl's rectangle.

d) A rectangle with width of 10 cm and length of 44 cm.

we will find the ratio of length by width.

\frac{length}{width}= \frac{44}{10} = \frac{11}{5} \ \ \ \ equation \ 2

By Definition of Similar rectangles which states that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1 \neq equation 2

Hence This rectangle is not similar to Carl's rectangle.

6 0
2 years ago
F(x)=2x^4+7x^3-2x^2-19x-12
kirill115 [55]

what do you need done with this question. like do you need it simplified or facotr by grouping what i need more info

7 0
2 years ago
Can someone help me with this question?
creativ13 [48]

Answer:

The answer is 3462.50 because it's being subtracted by 75% I think.

If not then it's 10387.5 because then it's being subtracted by 25%.

Hope I helped! ^^

(Can I please have brainliest?)

5 0
1 year ago
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