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Blababa [14]
2 years ago
10

Solve equation -1/9 / (-1/3)

Mathematics
2 answers:
alexgriva [62]2 years ago
6 0

Answer: 1/3

Step-by-step explanation:

-1/9 / -1/3 = ?

Keep: -1/9

Change: *

Flip: -3/1

Solve: -1/9 * -3/1 = 3/9

Simplify: 1/3

Dima020 [189]2 years ago
6 0

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathsf{-\dfrac{1}{9}\div - \dfrac{1}{3}}

\huge\textbf{Simplify it:}

\mathsf{-\dfrac{1}{9}\div - \dfrac{1}{3}}

\huge\textsf{Convert:}

\mathsf{= -\dfrac{1}{9} \times -\dfrac{3}{1}}

\huge\textsf{Multiply:}

\mathsf{= \dfrac{-1\times3}{9\times -1}}

\mathsf{= \dfrac{-3}{-9}}

\mathsf{= \dfrac{-3 \div -3}{-9\div-3}}

\mathsf{= \dfrac{1}{3}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\frak{\dfrac{1}{3}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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We must compute the derivatives and check if the equation is satisfied.

A. y'=(3\sin x)'=3\cos x. Differentiate again to get y''=(3\cos x)'=-3\sin x, then y''+y=-3\sin x+3\sin x=0\neq 3\sin x so this choice of y doesn't solve the equation.

B. y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x and y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x, then y''+y=10\sin x+6\cos x\neq 3\sin x so y is not a solution

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D.y'=-3\sin x and y''=-3\cos x, then y''+y=0 thus y isn't a solution

E. y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x hence y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x. Then y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x then y is not a solution.

3 0
3 years ago
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