Do you have a better picture?
Answer:
Sorry I don´t know the answer but I tried
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given expression : 
Solving further :


So, 
So, The given expression is equivalent to Option A
So, Option A is the answer
Answer:
A multiplicative inverse of a real number x is a real number y such that xy = 1. ... ((NOT GOOGLING DEF))
Step-by-step explanation:
"For every real number x, if x 0, then there is a real number y such that xy = 1.”