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Neporo4naja [7]
2 years ago
15

Correct the error 4⁴- 4³=4¹​

Mathematics
1 answer:
max2010maxim [7]2 years ago
3 0

The error is that

{x}^{y}  -  {x}^{z}  \neq {x}^{y - z}

Instead, it should be 4⁴ - 4³ = 256 - 64 = 192.

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Thirteen million three hundred and twentyfive thousand and sixty nine

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What is the measure of Question 3 options:<br><br><br> 40<br><br><br> 50<br><br><br> 60<br><br><br> 70
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5. What is the Domain?
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3 years ago
Find the circumference of the circle.
Studentka2010 [4]

Answer:

11\pi

Step-by-step explanation:

To find the circumference of a circle, the formula is:

d * \pi = c

We already know the diameter, so we just plug that in:

11 * \pi = c

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Let me know if you have any questions.

5 0
3 years ago
Rewrite in standard form of a circle<br> x^2-6x+y^2-4y-12=0​
cricket20 [7]

Answer: (x-3)^{2} + (y-2)^{2} = 5^{2}

Step-by-step explanation:

The standard form of equation of a circle is written in the form:

(x-a)^{2} + (y-b)^{2} = r^{2}

where a and b are the coordinates of the center and r is the radius.

All we need to do is to covert the given equation into this form, how do we do that?

We will achieve this by using the completing method of solving quadratic equation.

Firstly re - write the equation , that is

x^{2} - 6x + y^{2}-4y = 12

The next thing is to Complete the square for each of  x and y

How do we do this ?

i. multiply the coefficient of x and y by 1/2

ii. square the results

iii. Add the result to both sides of the equation , that is

x^{2} - 6x + 3^{2} - 4y + 2^{2} = 12 +3^{2}+2^{2}

The next thing is to write the Left hand side of the equation as a perfect square binomial and simplify the Right hand side. That is

(x-3)^{2} + (y-2)^{2} = 25 , that is

(x-3)^{2} + (y-2)^{2} = 5^{2}

Which is now in standard form of the equation of a circle.

6 0
3 years ago
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