Ask question

Ask question

All categories

Natali5045456 [20]

1 year ago

13

Erika has three pieces of ribbon. Each piece is 25 yards long. She needs to cut pieces that are 22 inches long. What is the grea

test number of 22-inch pieces that she can cut from the three pieces of ribbon?

1 answer:

nydimaria [60]1 year ago

4 0

She can cut 40 pieces of ribbon from it because there are 900 inches in 25 yards so you decide that by 22

You might be interested in

The attendance at the last Swoopes High basketball game was only 53 people. The school’s goal is to have at least 2 ½ times as m

Rina8888 [55]

The answer is 132 becuase 53x 2 1/2 = 132

I hope I helped you

3 0

2 years ago

Tthe rectangle below has an area of 12y^5 square meters and a width of 3y^3 meters

liq [111]

Answer:

$4y^2$

Step-by-step explanation:

$length \: of \: rectangle \\ = \frac{area}{width} \\ \\ = \frac{12 {y}^{5} }{3 {y}^{3} } \\ \\ = 4 {y}^{5-3} \\ \\ \red{ \bold{ length \: of \: rectangle = 4 {y}^{2} }}$

6 0

2 years ago

What is the surface area of the rectangular prism, if its length is 17 meters?

wel

182 m^ (Third answer) because it is not the volume

2 rectangles measuring 17x2 2(17x2)= 2x34 = 68 m^

2rectangles measuring 17x3 2(17x3)=2x51+102 m^

2rectangles measuring 3x2 2(3x2)=2x6=12 m^

TOTAL---------------------------------------------------------182 m^

8 0

2 years ago

If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\\\\=(3x+2)(2x-1)\\\\3x+2=0\to x=-\frac{2}{3}\\\\2x-1=0\to x=\frac{1}{2}\\\\\alpha=-\frac{2}{3};\ \beta=\frac{1}{2}\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{-\frac{2}{3}}{\frac{1}{2}}+\frac{\frac{1}{2}}{-\frac{2}{3}}=-\frac{2}{3}\cdot\frac{2}{1}-\frac{1}{2}\cdot\frac{3}{2}=-\frac{4}{3}-\frac{3}{4}\\\\=-\frac{16}{12}-\frac{9}{12}=-\frac{25}{12}=-2\frac{1}{12}$

$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

$6x^2+x-2\\\\a=6;\ b=1;\ c=-2\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{1^2}{6\cdot(-2)}-2=\frac{1}{-12}-2=-2\frac{1}{12}$

7 0

2 years ago

8 k+d use k=2 and d=3

sveta [45]

8×2=16

16+d

d=3

16+3=19

5 0

2 years ago