45m+10n-30m
15m+10n
I believe this is right.
Answer:
111 / 190
Step-by-step explanation:
Total biscuits = 20
Plain, P = 12
Chocolate, C = 5
Currant, K = 3
Assume without replacement :
Probability that biscuit are of the same type :
P(plain) :
12 / 20 * 11 / 19 = 132 / 380
P(chocolate) :
5/ 20 * 4 / 19 = 20/ 380
P(currant) :
3/20 * 2 /19 = 6 / 380
Therefore,
Probability that biscuit is of the same type :
P(plain) + P(chocolate) + P(currant)
132/380 + 20/380 + 6/380
158 / 380 = 79 / 190
Therefore, probability that biscuit aren't of the same type :
1 - P(biscuit is of same type)
1 - 79/190
(190 - 79) / 190
111 / 190
Answer:
(2,2) is the solution of the given lines.
Step-by-step explanation:
Given that,
y = x ..(1)
y = 3x-4 ...(2)
We need to find the coordinates of the point of intersection.
From equation (1) and (2).
x=3x-4
4 = 3x-x
4 = 2x
x = 2
Also,
y = 2
<h3>Hence, the coordinates of the point of intersection is (2,2).</h3>