Someone please help meee
1 answer:
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Answer:
v = 8.49 m/s rounded off to 3 significant figures
Step-by-step explanation
Using Energy Conservation
U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)
- At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
- Ui = 0 + mgh
- At ground all potential energy is converted to kinetic; hence, Uf =
mv².
- Since total energy of the system remains constant we equate Ui to Uf.
- Ui = Uf
- mgh =
- After cancelling out masses and making v the subject of the formula we get:
v = =
= 8.49 m/s rounded off to 3 significant figures