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AVprozaik [17]
3 years ago
14

Someone please help meee

Mathematics
1 answer:
zzz [600]3 years ago
6 0
B = -16
m = (-15-(-16))/18-0 = 1/18
y= 1/18x - 16
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Write $3.9 out of $60 as percentage​
Norma-Jean [14]

Answer:

Step-by-step explanation:

\frac{3.9}{60}*100=\frac{13}{2}

            = 6.5%

4 0
2 years ago
Complete a b and c if you do one it would mean alot
victus00 [196]

Answer: I don't see what your talking about here, so I can't help you.

Step-by-step explanation:

6 0
3 years ago
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Suppose you buy 4 buckets of apples and 5 buckets of peaches for $64. If you bought 8
Sophie [7]

Option D is the correct answer.

Step-by-step explanation:

Step 1 :

Let A represent the cost of one bucket of apple and P represent the cost of one bucket of peaches.

So we have ,

4 buckets of apples and 5 buckets of peaches for $64

8  buckets of apples and 3 buckets of peaches for $72

Writing this in the equation form we have,

4A + 5P = 64

8A + 3P = 72

Step 2:

Solving for the above 2 equations we can get the required costs

Equation 1 is

4A + 5P = 64 , Multiplying this by 2 we have 8A + 10P = 128

Equation 2  = 8A + 3P = 72

Subtracting both we have , 7p = 56 = > P = 8

Substituting this in equation 1 we have

8A + 80 = 128 => A = 6

Hence the cost of one bucket of apple is $6 and the cost of one bucket of apple is $8.

Option D is the correct answer.

3 0
3 years ago
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What is .74 repeating as a fraction?
Sedaia [141]
The answer to your question is 74/99:D
8 0
3 years ago
Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknig
pentagon [3]

Answer:

  1. Probability [No customers in system] = 0.375
  2. Customers waiting for service = 25/24
  3. Average time customer wait = 1.25/1.5
  4. May be wait
  5. Per customer average time = 1.33 (Approx)

Step-by-step explanation:

Given:

Arrival rate λ = 1.25 min

Mean μ = 2

Computation:

(a) Probability [No customers in system]

Probability [No customers in system] = 1-[λ/μ]

Probability [No customers in system] = 1-[1.25/2]

Probability [No customers in system] = 0.375

(b) Customers waiting for service

Customers waiting for service = λ²/ [μ(μ-λ)]

Customers waiting for service = 1.25²/ [2(2-1.25)]

Customers waiting for service = 25/24

(c) Average time customer wait

Average time customer wait = λ / [μ(μ-λ)]

Average time customer wait = 1.25/ [2(2-1.25)]

Average time customer wait = 1.25/1.5

(d) May be wait because Customers waiting for service = 25/24

(e) Per customer average time

Per customer average time = 1/(μ-λ)

Per customer average time = 1/(2-1.25)

Per customer average time = 1.33 (Approx)

7 0
2 years ago
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