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kolezko [41]
2 years ago
10

Calculate x for each of the following right angled triangles.

Mathematics
1 answer:
Sphinxa [80]2 years ago
7 0

\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}

<h3>(a) x = 6.5 cm </h3><h3>(b) x = 10 cm</h3><h3>(c) x = 7 cm</h3><h3>(d) x = 7.9 cm</h3>

Step-by-step explanation:

To find an unknown side of a right angled triangle we use a theorum called pythagorus theorum..

<h3>Formula :</h3>

(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2

(h)^2 = (p)^2 + (b)^2

<h3>therefore, </h3>

(a) hypotenuse = x cm, base = √30 cm, perpendicular = √12 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (√12)^2 + (√30)^2

→ x^2 = 12 + 30

→ x^2 = 42

→ x = √42

→ x = 6.480...

→ x = 6.5 cm. (approx)

<h3>___________________________</h3>

(b) hypotenuse = √300 cm, base = √200 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√300)^2 = (x)^2 + (√200)^2

→ 300 = x^2 + 200

→ x^2 = 300 – 200

→ x^2 = 100

→ x = √100

→ x= 10 cm.

<h3>___________________________</h3>

(c) hypotenuse = √66 cm, base = √17 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√66)^2 = (x)^2 + (√17)^2

→ 66 = x^2 + 17

→ x^2 = 66 – 17

→ x^2 = 49

→ x = √49

→ x = 7 cm.

<h3>___________________________</h3>

(d) hypotenuse = x cm, base = 5√12 cm,perpendicular = 2√3 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (2√3)^2 + (5√12)^2

→ x^2 = 12 + 50

→ x^2 = 62

→ x = √62

→ x = 7.874...

→ x = 7.9 cm. (approx)

<h3>___________________________</h3>

<h3>Hope it helps you!!</h3>
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