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Virty [35]
3 years ago
14

HELP AM BEING TIMED !!!!

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

Option B.

Step-by-step explanation:

It is given that triangle GFH has vertices G(2, –3), F(4, –1), and H(1, 1).

The triangle is rotated 270° clockwise using the origin as the center of rotation. So, rule of rotation is defined as

(x,y)\to (-y,x)

Now,

G(2,-3)\to G'(3,2)

F(4,-1)\to F'(1,4)

H(1,1)\to H'(-1,1)

So, the vertices of image are G'(3,2), F'(1,4) and H'(-1,1).

Therefore, the correct option is B.

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3 years ago
What is the vertex form of the quadratic equation represented on the table?
sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}

7 0
2 years ago
(02.02 HC)
Dima020 [189]
Hey there!

It seems as if you found the answer to your problem?  If you need any help though, just let me know!

Let me know if you'd like me to explain how I got this answer!
3 0
4 years ago
Can you please help me thank yo
d1i1m1o1n [39]
This one is also going to be b
7 0
4 years ago
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