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Mars2501 [29]
2 years ago
8

What is the length of a diagonal of a rectangle with a length of 8 meters and a width of 6 meters

Mathematics
1 answer:
RSB [31]2 years ago
7 0

Answer:

10 m

Step-by-step explanation:

If we draw the diagonal of the rectangle, we form a right triangle where the diagonal is the hypotenuse and the legs are 6 and 8.

This is a well-known Pythagorean triple, which gives the diagonal to be 10 m.

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What is the simplified form of expression<br> -4xy/3x
DiKsa [7]

Answer:

(-4/3)y

Step-by-step explanation:

The x cancels out, leaving:

-4y/3 or (-4/3)y

7 0
3 years ago
The first term is 8 Each term is 4 more than double the previous term.
xz_007 [3.2K]

Answer:

8*2^(n-1)

Step-by-step explanation:

This is a geometric sequence since we multiply from the previous term.

a_n = a_1 * common ratio^(n-1) where a_n is the nth number and a_1 is the first.

The first term is 8, so we have

a_n = 8*<common ratio>^(n-1) = 8*2^(n-1)

5 0
3 years ago
Read 2 more answers
What is the scale factor of the two triangles below?
vodka [1.7K]
Answer:

3/4

Explanation:

15 is 3/4 of 20
3 is 3/4 of 4
6 is 3/4 of 8
6 0
4 years ago
What 2 numbers add up to 17 and multiply to get -84?
kicyunya [14]
21 and -4, because -4x21 = -84, and 21+-4 (– 4) = 17
6 0
3 years ago
Find the measure of angle eight in each triangle round each answer to the nearest 10th
vlada-n [284]

Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

  and hypotenuse sides

∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

∴ m∠A = cos^{-1}\frac{5.4}{6}=25.84193

* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

∵ EA = 6.8 ⇒ the hypotenuse

- To find m∠A use the sine function because we have opposite

  and hypotenuse sides

∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

3 0
3 years ago
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