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cricket20 [7]
3 years ago
11

Please help!!! 15 points

Mathematics
1 answer:
12345 [234]3 years ago
6 0
It should be C according to my knowledge
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How do you write the indicated form of a function for an absolute value equation?
timama [110]
Attached solution and work.

3 0
3 years ago
What is the solution to x- 9> -15?
Elanso [62]

Answer:

x < -6

Step-by-step explanation:

quick explanation: when you transfer (-9) to the other side it becomes +9.

Therefore, -15+9= -6

4 0
3 years ago
T<br> ✓<br> Х<br> Find the sum of (x2 – 7x + 5) and (-3x2 - x + 10)<br> [
Zanzabum

Answer:

-2x² - 8x + 15 = 0

Step-by-step explanation:

Given the following algebraic expression;

x² – 7x + 5

-3x² - x + 10

To add the equation together;

x² – 7x + 5 + (-3x² - x + 10) = 0

x² – 7x + 5 - 3x² - x + 10 = 0

Collecting like terms, we have;

(x² - 3x²) - (7x + x) + (5 + 10) = 0

-2x² - 8x + 15 = 0

8 0
3 years ago
The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random
Zanzabum

1) Mean: 6.5

2) Standard deviation: 3.2

Step-by-step explanation:

1)

A uniform random distribution is the distribution of a variable that can assume n different values, and each of these values is equally likely to occur.

This means that the probability of occurring of each of these values is the same:

p(x_1)=p(x_2)=...=p(x_n)

For a uniform random distribution, the mean of the distribution is simply equal to the median value of the distribution, which is exactly at the center of the distribution itself. It can be calculated as

\bar x = \frac{1}{2}(a+b)

where

a is the lowest value of the distribution

b is the highest value of the distribution

Here the distribution consists of all values ranging from 1 to 12, so:

a = 1

b = 12

Therefore the mean value is

\bar x=\frac{1}{2}(1+12)=6.5

2)

For a uniform random distribution, it can be dimostrated that the variance of the distribution is

\sigma^2 = \frac{1}{12}(b-a)^2

For the distribution in this problem, we have:

a = 1

b = 12

Therefore the variance is

\sigma^2 = \frac{1}{12}(12-1)^2=10.08

The standard deviation is the square root of the variance, therefore for this distribution it is:

\sqrt{\sigma^2}=\sqrt{10.08}=3.2

Learn more about mean and standard deviation:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

3 0
3 years ago
Given f(x)=10(3−x)+6, what is the value of f(−1)?
Ber [7]

Answer: 46

Step-by-step explanation:

10 (3 +1) + 6

30 + 10 + 6

46

5 0
3 years ago
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