Answer:
Fraction of bread used in the recipe is 3/12 which can be further simplified into 1/4
Explanation:
The original loaf of bread is 100% complete (no fraction is taken from it yet). This means that the value of the original loaf is 12/12
Now, assume that the fraction used in the recipe is x
We know that:
2/12 of the loaf was used in making a sandwich
7/12 of the oaf was put in the refrigerator
Therefore:
complete loaf = fraction used in making a sandwich + fraction used in making recipe + fraction put in refrigerator
12/12 = x + 2/12 + 7/12
12/12 = x + 9/12
x = 12/12 - 9/12
x = 3/12
Hope this helps :)
Answer:13.5
Step-by-step explanation:
the answer is 13.5
1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn
alisha [4.7K]
Answer and explanation:
Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.
To find : Determine each of the following,
a) 
b) 
c) 
d)
Solution :
The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.
The intersection of two sets is a new set that contains all of the elements that are in both sets.
a) 

Then, 
b) 



c) 


d) 




Answer:
Step-by-step explanation:
For problem 10:
1. AE/ED=AC/CB (Since triangle ABC is similar to triangle ADE, we can determine that the ratio of AE to ED is equal to the ratio of AC to CB)
2. AE/ED=(AE+EC)/CB (Rewrite AC as the sum of the lengths forming it; This is sometimes referred to as the Partition Postulate)
3. 9/x=(9+6)/10 (Substitute the given values into this equation)
4. x=6 (Use algebra to solve for x)
For problem 11:
1. AG/AB=AE/AD (Use the same strategy as step one in problem 10, since the rectangles are similar we can create this equation)
2. AG/(AG+GB)=AE/(AE+ED) (Rewrite sides as the some of their parts)
3. 14/(14+7)=18/(18+x) (Substitute given values)
4. x=9 (Solve for x)
lmk if there are mistakes in my explanation, hope this helps :)