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Assoli18 [71]
2 years ago
14

A sample of 50 11th graders were asked to select a favorite pattern out of 6 choices. The data list below shows what their favor

ite color patterns were, and the accompanying frequency table and bar graph represent these data. In the bar graph, the height of the blue-gray bar is 4, the height of the green bar is 9, and so on.
Suppose that, rather than being just a bar graph, the display you see above is a relative frequency bar graph. The vertical axis of the graph will be marked off in percentages, from 0 percent up to 30 percent. What will be the height of the green bar?

A.
15

B.
25

C.
9

D.
18

Mathematics
1 answer:
Helen [10]2 years ago
7 0

Answer:

D 18

Step-by-step explanation:

100% = 50 (all students)

1% = 100%/100 = 50/100 = 1/2 = 0.5

we get any percentage for any number by dividing the number by 1% (0.5) to see how often it fits in.

there are 9 votes for green.

9/ 0.5 = 18%

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A rope is cut into three pieces P, Q, and R the lengths of the pieces are in the ratio 3:5:7 if the rope is 33 feet 9 inches, fi
Olin [163]
P-81
q-135
r-189
find out how many inches the rope is then divide by 15 total parts then multiply each ratio by that
4 0
3 years ago
What is the equation of the line? Plsss helppp
Goshia [24]

Answer:

y = -7

Step-by-step explanation:

Slope: 0

y-intercept: (0,−7)

Since the line doesn't change up, down, right, or left, and it stays on the y-axis, that's how u get y = . The straight line runs along -7 . That's how u get -7 . so when u put it all together u get: y = -7 .

Hope that helps. Tried to explain the best I could :)

5 0
2 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
How many solutions are there to the equation below?<br> 8x + 47 = 8(x + 5)
qaws [65]

Answer:

there are 0 solutions to the equation

Step-by-step explanation:

To know how many solutions are in the problem, we have to solve for x and see what result we have left. According to the result, we will know how many solutions there are

8x + 47 = 8(x + 5)

8x + 47 = 8*x + 8*5

8x + 47 = 8x + 40

8x - 8x = 40 - 47

0 = -7

As we can see we are left with an equality that is not fulfilled, this means that there is no solution to the problem, at least in the field of real numbers

4 0
2 years ago
3:9 in simpliest form
Softa [21]

Answer:

1:3

Step-by-step explanation:

3    divide 3    1

9    divide 3    3

5 0
3 years ago
Read 2 more answers
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