301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
Answer:
(4 + 7i)(4 – 7i)
Step-by-step explanation:
This pair will produce a real answer because they are complex conjugates.
Complex conjugates ( a+bi) (a-bi) when multiplied together form a real number ( a^2 + b^2)
Answer:
6a-6n+36
Step-by-step explanation:
-10a-9n+16-30+3n+15a+50+a
Combine a...
-10a+15a= 5a+a=6a
Combine n...
6a-9n+16-30+3n+50
-9n+3n= -6n
6a-6n+ 16-30+50
Combine # w no variable
Answer: 6a-6n+36
Answer:
1287
Step-by-step explanation:
Is means equals and of means multiply
W = 130% * 990
Change to decimal form
W = 1.30 * 990
W =1287
Answer:
no
Step-by-step explanation:
Two rectangles having the same area do not need to have the same length and width. The length and width of the rectangle are just factor pairs of the number that is the area. For example, if the area was 12, the side lengths would be 1 and 12, 2 and 6, or 3 and 4. As you can see, those aren't the same lengths and widths. A rectangle may be 1x12 and another may be 3x4, but they have the same area.
