Answer:
The answer is a circle. Sorry if it is too late to help you. Maybe it will help someone else.
Step-by-step explanation:
I just took a test with the same question. Proof of right answer is attached.
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Answer:
48y⁶w¹¹
Step-by-step explanation:
[-3y⁵][4y] → -12y⁶
×
[w³][-4w⁸] → -4w¹¹
______
48y⁶w¹¹
I am joyous to assist you anytime.
Answer:
The second one decreasing on the interval (-infinity, 0) where it becomes constant
