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Oksi-84 [34.3K]

2 years ago

9

A^4 b^2÷4a^3 b^-2

7B3%7D%20%20%7Bb%7D%5E%7B%20-%202%7D%20" id="TexFormula1" title=" {a}^{4} {b}^{2} \div 4 {a}^{3} {b}^{ - 2} " alt=" {a}^{4} {b}^{2} \div 4 {a}^{3} {b}^{ - 2} " align="absmiddle" class="latex-formula">

1 answer:

hichkok12 [17]2 years ago

7 0

A^7 /4
That is the simplification

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Please answer and show steps please show steps please show steps 10 points

natali 33 [55]

Answer:

it is C 10

Step-by-step explanation:

If the positions are distinct, as in executive offices, then P(9, 5).

P(9, 5) = 9!/(9 - 5)! = 15120

If the positions are equivalent, such as seats in a legislative body, then C(9, 5).

C(9, 5) = 9!/[(9 - 5)!(5!)] = 126

Assuming the five positions are unique in their duties and responsibilities (i.e. order matters): position 1 has 9 candidates to choose from, position 2 has 8, position 3 has 7, and so on. Otherwise, if you're talking about 5 distinct but duplicate positions - meaning their responsibilities are the same but 5 people are required to carry them out - you need to divide the previous total number of possibilities by the number of ways those possibilities could have been reordered.

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In Area A, the insurance coverage rate for a wood frame house is 0.46%. In Area B, the insurance coverage rate for a wood frame

Karo-lina-s [1.5K]

To solve for the homeowner's insurance payment for house built in Area B, we simply multiply the cost of the house with the insurance coverage rate in its decimal equivalent. From the given problem,
annual insurance payment = ($65,900)(0.0054)
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Thus, the answer is letter A.

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I need help with 4ourth grade math lesson 8 homework helper asap math

Dmitriy789 [7]

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Step-by-step explanation:

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Picture please because I can’t help without a picture or something

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3 years ago

The national mean annual salary for a school administrator is $90,00 a year (The Cincinnati Enquirer, April 7, 2012). A school o

timurjin [86]

Answer:

a) Null hypothesis: $\mu = 90000$

Alternative hypothesis: $\mu \neq 90000$

b) $p_v =2*P(t_{(24)}$

c) If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

77600 ,76000 ,90700 ,97200 ,90700 ,101800 ,78700 ,81300 ,84200 ,97600 ,

77500 ,75700 ,89400 ,84300 ,78700 ,84600 ,87700 ,103400 ,83800 ,101300

94700 ,69200 ,95400 ,61500 ,68800

We can calculate the sample mean and deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

The values obtained are:

$\bar X=85272$ represent the mean annual salary for the sample

$s=11039.23$ represent the sample standard deviation for the sample

$n=25$ sample size

$\mu_o =90000$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean salary differs from 90000, the system of hypothesis would be:

Null hypothesis: $\mu = 90000$

Alternative hypothesis: $\mu \neq 90000$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{85272-90000}{\frac{11039.23}{\sqrt{25}}}=-2.141$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=25-1=24$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(24)}$

Part c: Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

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4 years ago