$\dfrac{10(\cos 45^\circ + i \sin 45^\circ)}{5 (\cos 15^\circ + i \sin 15^\circ)} = \dfrac{10}{5} (\cos(45^\circ - 15^\circ) + i \sin(45^\circ - 15^\circ))$

$= 2(\cos 30^\circ + i \sin 30^\circ)$

Answer: $2(\cos 30^\circ + i \sin 30^\circ)$

That's probably what's called simplified polar form until you get to Euler's Formula. Since it's 30 degrees we can get a nice rectangular form:

$2(\cos 30^\circ + i \sin 30^\circ) = 2\left( \dfrac{\sqrt{3}}{2} + i \dfrac 1 2 \right) = \sqrt{3} + i$

7 0

2 years ago

Helllllllllllllllllllllllllp i am putting all of my coin stuff up.

Kobotan [32]

Answer: uhhh so where is the question? You need a picture or an image to show the question or you can write it down?

Step-by-step explanation:

7 0

2 years ago

Tidal energy is powered by:

Pani-rosa [81]

Tidal energy is powered by <u><em>the moon's gravity</em></u>

7 0

1 year ago