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stiv31 [10]
2 years ago
15

Question 19 of 25

Mathematics
1 answer:
asambeis [7]2 years ago
4 0
It is going to b (4.12)
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Find the degree of the polynomial -2х2 +х+ 2.
storchak [24]

Answer:

Step-by-step explanation:

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3 0
3 years ago
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The y coordinate of the vertex of f (x)=-x^2+8x+7 is f(4)
azamat

Hello there.

To answer this question, we need to remember some properties about the vertex of quadratic functions.

Let f(x)=ax^2+bx+c,~a\neq0. Its vertex can be found on the coordinates (x_v,~y_v) such that x_v=-\dfrac{b}{2a} and y_v=-\dfrac{b^2}{4a}+c, in which y_v=f(x_v).

Using the coefficients given by the question, we get that:

x_v=-\dfrac{8}{2\cdot(-1)}\\\\\\ x_v=-\dfrac{8}{-2}\\\\\\ x_v=4

Thus, we have:

y=f(x_v)=f(4)

So the statement is true, because the x coordinate of the vertex of the function is equal to 4.~~\checkmark

7 0
3 years ago
Write a equation that represents the line
Phoenix [80]
Where’s the picture?
6 0
3 years ago
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Which is the simplified form of
AnnZ [28]

Answer: \frac{1}{r^{7} } +\frac{1}{s^{12} }

Step-by-step explanation:

With negative powers, r^{-7}  = \frac{1}{r^{7} }

do the same for s too

6 0
3 years ago
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Write the equation of this circle in standard form. A) (x - 2)2 + (y - 3)2 = 4
Vika [28.1K]

Answer:

x^2 + y^2 -4x -6y + 9 = 0

Step-by-step explanation:

To write a circle in standard form, expand the equation of the circle and move all terms to one side.

(x-2)^2 + (y-3)^2 = 4\\x^2 -4x + 4 + y^2 -6y + 9 = 4\\x^2 +y^2 - 4x - 6y + 13 = 4\\x^2 + y^2 -4x -6y + 9 = 0

8 0
3 years ago
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