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skelet666 [1.2K]
3 years ago
5

In the spinner below, what is the probability of landing on 5?

Mathematics
2 answers:
pantera1 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

D

kenny6666 [7]3 years ago
3 0

Answer:

D

Step-by-step explanation:

................................

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You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
Uber charges a $5 pickup fee and $0.25 per mile. define variables and write an equation to model this situation.
Degger [83]

Answer:

See below

Step-by-step explanation:

<h3>Uber</h3>
  • $5 pickup fee
  • $0.25 per mile

<u>Equation</u>

  • y = 0.25x + 5

<u>Cost of 5 miles:</u>

  • y = 0.25(5) + 5 = $6.25
<h3>KC yellow Cab Co.</h3>
  • $1.75 pickup fee
  • $0.75 per mile

<u>Equation</u>

  • y = 0.75x + 1.75

<u>Cost of 5 miles:</u>

  • y = 0.75(5) + 1.75 = $5.5

Comparing the cost we see KC yellow Cab Co. is better value for a 5 mile ride.

8 0
3 years ago
I need help understanding how to do the problem
notsponge [240]
So.. if you notice the picture below

is really just 3/4 of a cylinder, or, a full cylinder, and then you slice 1/4 off of it
notice the right-angle in your picture at the bottom, is cut at a right-angle, meaning, the cutout is 1/4 of the volume

so \bf \textit{volume of a cylinder}\\\\&#10;V=\pi r^2 h\qquad &#10;\begin{cases}&#10;r=radius\\&#10;h=height&#10;\end{cases}\qquad \frac{3}{4}\textit{ of that}\implies \cfrac{3}{4}\cdot \pi r^2 h

4 0
3 years ago
A livestock company reports that the mean weight of a group of young steers is 1143 pounds with a standard deviation of 88 pound
malfutka [58]

Answer:

<em>a) P(x<1200)=74.14%</em>

<em>b) P(1100<X<1250)=57.54%</em>

Step-by-step explanation:

<u>Normal Distribution</u>

The normal distribution, also known as the bell curve, is a distribution that occurs naturally in many situations of life. We use the model N(\mu,\sigma) to understand the behavior of some real-life variables. Where \mu is the mean value and \sigma is the standard deviation.

In our case, we have

\mu=1143,\ \sigma=88

And are required to find the percentage of steers whose weigh lie within a given range. We must use some sort of table or digital means to compute the values because the normal distribution cannot be calculated directly by a formula. We use the NORMDIST (or NORM.DIST) formula for Excel which gives us the left tail of the area behind the bell curve, i.e. the cumulative percentage for a give value of X. The formula has the form

NORM.DIST(x,mean,standard_dev,cumulative)

a) X<1200

The formula is used with the following parameters

NORM.DIST(1200,1143,88,true)

and we get

P(X

b) We need to compute P(1100<X<1250). To do this, we calculate both left tails and the subtract them

NORM.DIST(1100,1143,88,true)=0.3125

NORM.DIST(1250,1143,88,true)=0.8880

P(1100

\boxed{P(1100

6 0
2 years ago
How do you find the mean to MAD ratio?
OleMash [197]
Ask the question it should take you to a easy person answering your question.
3 0
3 years ago
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