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valentinak56 [21]
2 years ago
6

Given A(2, 3) B(1, 4) C(1, 3) D(-2, 2). How are AB and CD related?

Mathematics
1 answer:
kondaur [170]2 years ago
3 0

The vector AB is not related with the vector CD as k is not the same for each pair of components.

<h3>Are two vectors similar?</h3>

In this question we must prove if the vector AB is a multiple of the vector CD, that is:

\overrightarrow{AB} = k \cdot \overrightarrow {CD}

\vec B - \vec A = k \cdot [\vec D - \vec C]

(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]

(- 1, 1) = k · (- 3, - 1)

Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.

To learn more on vectors: brainly.com/question/13322477

#SPJ1

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Sophia and Olivia shared 60p so that Olivia had 10p more than Sophia. How much did Sophia have?
Taya2010 [7]

Answer:

25

Step-by-step explanation:

If Olivia had 10 more p than Sophia, then Olivia has 35, and Sophia has 25.

35 + 25 = 60!

3 0
3 years ago
How do you graph y=12/x
Tpy6a [65]

Answer: \frac{12}{x} is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=\frac{12}{2} =6. That's one of the points on the graph that we just found (2,6)

7 0
1 year ago
1.Find the zeros of f(x) = x2 - 9
Marat540 [252]
So for the first one it is (x-3)(x+3) this is because it is a difference of squares so you square root the 9 and the minus you do both +and - in order to keep up the -9
The zeros are:x=3 and x=-3 ( this is because you change the sign in the bracket


the others should be pretty simple to do for number 2 its a complex
the third is a simple trinomial
and fourth is simple trinomial as well
6 0
3 years ago
The list price of a diamond ring is $662. The jeweler is offering a chain discount of 15% less 10%. What is the final net price
Tom [10]
Your answer is 506.44.

multiply 662 x .10 now minus that answer from 662 to get 595.80

now multiply that by .15

now minus that by 595.80

gives you 506.43
4 0
2 years ago
200 labourers need 50 days to construct a road of 4 km long. How many labourers are needed to construct 8 km long in 80 days​
patriot [66]

Answer:

250

Step-by-step explanation:

Number of labourers * Number of days worked = Total number of working days

Total number of working days to construct a 4km long road: 200*50=10000

Total mumber of working days to construct a 8km long road: 10000*2=20000

Labourers: 20000 ÷ 80 = 250.

250 labourers are required.

7 0
3 years ago
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