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Dafna1 [17]
3 years ago
12

What is 6.025 as a fraction

Mathematics
2 answers:
Svetllana [295]3 years ago
5 0
<span>6025/1000 for a decimal fraction</span>
madreJ [45]3 years ago
4 0
The answer is 241/40 (I used a calculator)
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Mariulka [41]

Answer:

a=13m

Step-by-step explanation:

that's it in the picture

6 0
2 years ago
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Uhh I got this answer wrong my brain wasn’t working so I guessed and picked wet and salty
Dahasolnce [82]

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dry and hot

Step-by-step explanation:

It looks very similar to a cactus which also lives in this in a dry and hot area

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3 years ago
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Part of the population of 6,750 elk at a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that 3 o
Anastasy [175]

Answer:

405

Step-by-step explanation:

We can use a ratio to solve

3 infected           x infected

------------------ = ----------------

50 sampled     6750 population

Using cross products

3*6750 = 50x

Divide each side by 50

3*6750/50 = x

405

7 0
3 years ago
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1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Convert the following equation into<br> standard form.<br> y = -5x + 2<br> 5x + [?]y = [ ]
antiseptic1488 [7]

Answer:

standard form is Ax + by + c = 0

Step-by-step explanation:

add 5x to each side to get 5x + y - 2 = 0

6 0
3 years ago
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