There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Answer:
54
Step-by-step explanation:
Answer:
0.55
Step-by-step explanation:
diference= 25/100*2.20=0.55
Answer:
A. 4 2/3 hours
B. (i) 9 4/5 hours
(ii) 1 19/30
Step-by-step explanation:
Firstly, to find the number of hours he used in visiting old folks, what we have to do is to multiply the fraction of hours he used by the total number of hours.
Mathematically, that would be;
4/7 * 8 1/6
8 1/6 is same as 49/6
So the number of hours he spent visiting old folks would be ;
49/6 * 4/7 = 14/3 = 4 2/3 hours
B. What we do here is simply multiply the fraction now by what he spent last year.
That would be 1 1/5 * 8 1/6 hours
= 6/5 * 49/6 = 49/5 = 9 4/5 hours
ii) Now we want to know how much more time will be spent this year than last year.
What to do here simply is to subtract the time taken last year from what we have this year
That would be;
49/5 - 49/6 = 49/30 = 1 19/30
So this means they just fliped the numbers around
