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1 year ago

What is the equation of the line that passes through the point (-6,8) and has a slope of -5/3?

Mathematics

1 answer:

Alexxx [7]1 year ago

7 0

Answer:

y = -5/3 - 8

Step-by-step explanation:

We want to write this in the form y = mx + b. We need to find the m (slope) and the b (y-intercept) , Whew, they already gave us the slope, so we are have way there. I will plug in the x and y that we are given from the point (-6, 8) to solve for b.

y = mx + b

8 = -5/3(-6) + b Multiply the fraction by -6

8 = 30/3 + b I can make 6 a fraction by writing it 6/1 and then just multiply straight across. A negative times a negative is a positive.

8 = 10 + b 30/3 is equal to 10. Now subtract 10 from both sides to get b

-8 = b

I can now write the equations since I now know m and b.

y = -5/3 + (-8) which is the same as y = -5/3 - 8. Adding a negative is the same as subtracting a positive.

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In how many ways can six people sit in a six-passenger car?

nekit [7.7K]

Answer:

number of ways = 720

Step-by-step explanation:

The number of ways six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then

number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720

Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.

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3 years ago

Help please, this is a math question. <3

AfilCa [17]

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2 years ago

Read 2 more answers

Convert each of the following estimates of useful life to a straight-line depreciation rate, stated as a percentage: (a) 10 year

Rzqust [24]

Answer:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

Step-by-step explanation:

Under straight line method of depreciation, equal amount of the depreciation is reduced throughout the useful life of the asset. Using the following formula:

<u>Straight line depreciation rate = 1 / Useful Life x 100 </u>

So:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

7 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$