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tamaranim1 [39]
2 years ago
13

What is the equation of the line that passes through the point (-6,8) and has a slope of -5/3?

Mathematics
1 answer:
Alexxx [7]2 years ago
7 0

Answer:

y = -5/3 - 8

Step-by-step explanation:

We want to write this in the form y = mx + b.  We need to find the m (slope) and the b (y-intercept) ,  Whew, they already gave us the slope, so we are have way there.  I will plug in the x and y that we are given from the point (-6, 8) to solve for b.

y = mx + b

8 = -5/3(-6) + b  Multiply the fraction by -6

8 = 30/3 + b  I can make 6 a fraction by writing it 6/1 and then just multiply straight across.  A negative times a negative is a positive.

8 = 10 + b   30/3 is equal to 10.  Now subtract 10 from both sides to get b

-8 = b

I can now write the equations since I now know m and b.

y = -5/3 + (-8) which is the same as y = -5/3 - 8.  Adding a negative is the same as subtracting a positive.

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What is the vertex of the graph of f(x) = x2 + 4x + 6?
ICE Princess25 [194]

Answer:

(-2,2)

Step-by-step explanation:

6 0
3 years ago
Which expressions are equivalent?
storchak [24]
The answer is A.) 3x-7y and -7y+3x
This is due to "3x" implies the value is positive, or "+3x", and -7y remains -7y.
So, we have 3x-7y and -7y+3x.

I hope this helps!
4 0
3 years ago
Read 2 more answers
Which is smaller 1&5/8"or 1&7/8"
grigory [225]
1 & 5/8 because 7/8 is closer to 1 whole than 5/8
4 0
3 years ago
Solve the system of equations: <br> X+y+z=5<br> -3x-4y+4z=15<br> 2x-y-4z=-8
atroni [7]

Answer:

  (x, y, z) = (3, -2, 4)

Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

  z = 5 -(3 +(-2)) = 4

The solution is (x, y, z) = (3, -2, 4).

__

Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

  \left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]

__

If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

  -3x -4y +4(5 -x -y) = 15   ⇒   -7x -8y = -5

  (-3x -4y +4z) +(2x -y -4z) = (15) +(-8)   ⇒   -x -5y = 7

This pair of equations can be solved for x and y in any of the usual ways. Using the second equation to substitute for x, for example, gives you ...

  -7(-5y -7) -8y = -5   ⇒   27y = -54   ⇒   y = -2

  x = -5(-2) -7 = 3

  z = 5 -(3) -(-2) = 4

_____

<em>Additional comment</em>

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

6 0
2 years ago
Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0
Tom [10]
For this case we have the following expression:
 (xy ^ -6) / (x ^ -4y ^ 2)
 By power properties we can rewrite the expression as:
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 Then, for power properties:
 Same exponents are added:
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 (x ^ 5) / (y ^ 8)
 Answer:
 
An expression after the negative exponents have been eliminated is:
 
(x ^ 5) / (y ^ 8)
3 0
3 years ago
Read 2 more answers
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