Answer:
I wanna say its all real numbers
Step-by-step explanation:
The quotient of the provided division in which binomial is divided by a quadratic equation is x+2.
<h3>What is the quotient?</h3>
Quotient is the resultant number which is obtained by dividing a number with another. Let a number <em>a</em> is divided by number b. Then the quotient of these two number will be,

Here, (a, b) are the real numbers.
The given division expression is,

Let the quotient of this division problem is f(x). Thus,

Factor the numerator expression as,

Thus, the quotient of the provided division in which binomial is divided by a quadratic equation is x+2.
Learn more about the quotient here;
brainly.com/question/673545
Subtract 2_5/8 minus 1_1/3:
First, get the fractions to have a common denominator by multiplying the denominators together: 8*3 = 24
Rewrite both fractions with this new denominator:
5/8 needs to be multiplied by 3 on top and bottom to make it have a denominator of 24:
5/8 * 3/3 = 15/24
1/3 needs to be multiplied by 8 on top and bottom to make it have a denominator of 24:
1/3 * 8/8 = 8/24
Now that the fractions have been rewritten with the same denominator, subtract the mixed numbers:
2_15/24 - 1_8/24
Whole numbers:
2 - 1 = 1
Fractions:
15/24 - 8/24 = 7/24.
The can of condensed soup contains 1_7/24 cup
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
