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3 years ago

Find the solutions of this quadratic. f(x)=(x-8)(x+4)

Mathematics

1 answer:

Studentka2010 [4]3 years ago

3 0

$x1 = 8 \\ x2 = - 4$

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How do I solve this problem??

choli [55]

They're the same like integers.
First you should interpret it.
For example:
a. -3x + 8x is the same like -3 + 8. You just add x.
Which is 5x.

3 0

3 years ago

If 1-cosA = 1/2 , Then find the value of sinA.

zimovet [89]

Step-by-step explanation:

Given :

1- cosA = 1/2

or, CosA = 1 -1/2

Therefore ; CosA = 1/2 = b/h

According to the Pythagoras theorem,

P = root under h^2 - b^2

= root under (2)^2 - (1)^2

= root under 4 -1

= root 3

Again,

SinA = P/h

= root 3 / 2

8 0

2 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago

What are the following numbers from least to greatest 14/5, -2.46, -10/4, 2.5

Vera_Pavlovna [14]

Answer:

-2.46, -10/4, 14/5, 2.5.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Divide the sum of (-24),(-10) and (-40) by the product of (-5) and 3

PilotLPTM [1.2K]

Answer:

4.93333...

Step-by-step explanation:

-24 + (-10) + (-40) = -74

-5 * 3 = -15

-74 /-15 = 4.93333...

5 0

3 years ago

Read 2 more answers