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Lyrx [107]
2 years ago
9

What is the factored form of 27 - 530?

Mathematics
1 answer:
Iteru [2.4K]2 years ago
4 0
It’s the last choice
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marin [14]

Answer:the diagonal lengths are equal

Step-by-step explanation:

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2 years ago
Help me i beg u plzzzz
Ainat [17]
We can say at month 0 she was 43 inches tall.

And at month 18 she was 52 inches tall.

We can say that x is the number of months and y is her height.

Rise/run
y2-y1/x2-x1
52-43/18-0
9/18
1/2

So the slope is 1/2 (which is what you are looking for.) and if you were to write an equation it would be y=1/2x+43

Brainliest my answer if it helps you out?
5 0
3 years ago
Let X ~ N(0, 1) and Y = eX. Y is called a log-normal random variable.
Cloud [144]

If F_Y(y) is the cumulative distribution function for Y, then

F_Y(y)=P(Y\le y)=P(e^X\le y)=P(X\le\ln y)=F_X(\ln y)

Then the probability density function for Y is f_Y(y)={F_Y}'(y):

f_Y(y)=\dfrac{\mathrm d}{\mathrm dy}F_X(\ln y)=\dfrac1yf_X(\ln y)=\begin{cases}\frac1{y\sqrt{2\pi}}e^{-\frac12(\ln y)^2}&\text{for }y>0\\0&\text{otherwise}\end{cases}

The nth moment of Y is

E[Y^n]=\displaystyle\int_{-\infty}^\infty y^nf_Y(y)\,\mathrm dy=\frac1{\sqrt{2\pi}}\int_0^\infty y^{n-1}e^{-\frac12(\ln y)^2}\,\mathrm dy

Let u=\ln y, so that \mathrm du=\frac{\mathrm dy}y and y^n=e^{nu}:

E[Y^n]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu}e^{-\frac12u^2}\,\mathrm du=\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu-\frac12u^2}\,\mathrm du

Complete the square in the exponent:

nu-\dfrac12u^2=-\dfrac12(u^2-2nu+n^2-n^2)=\dfrac12n^2-\dfrac12(u-n)^2

E[Y^n]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{\frac12(n^2-(u-n)^2)}\,\mathrm du=\frac{e^{\frac12n^2}}{\sqrt{2\pi}}\int_{-\infty}^\infty e^{-\frac12(u-n)^2}\,\mathrm du

But \frac1{\sqrt{2\pi}}e^{-\frac12(u-n)^2} is exactly the PDF of a normal distribution with mean n and variance 1; in other words, the 0th moment of a random variable U\sim N(n,1):

E[U^0]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{-\frac12(u-n)^2}\,\mathrm du=1

so we end up with

E[Y^n]=e^{\frac12n^2}

3 0
2 years ago
Rachel weighed her two cats, Tiger and Mittens. Tiger weighed 10.91 pounds, and Mittens weighed 178.08 ounces. Which cat is heav
Dafna11 [192]

Answer:

answer is c

Step-by-step explanation:

178.08 oz = 11.13 lb

11.13-10.91 = 0.22 lb

4 0
2 years ago
Picture of problem below NO LINKS
iragen [17]

Answer:

600$

Step-by-step explanation:

I think this is right

5 0
3 years ago
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