A.match the expressions on the left with the with the illustrations on the right
1 answer:
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The measure of ∠DBC is 36°
In the circle, BD is the diameter and BC is the minor chord on the circle, due to which ∠BCD = 90°, in triangle BDC
Then,
Given arc BD measure is 54° i.e ∠BDC is 54°
The, from property of triangle, sum of all angles is 180°, we can find the third angle i.e. ∠DBC.
Thus, ∠DBC = 180°- 90°- 54°
∠DBC = 36°
In the circle, BD is the diameter and BC is the minor chord on the circle, due to which ∠BCD = 90°, in triangle BDC
Then,
Given arc BD measure is 54° i.e ∠BDC is 54°
The, from property of triangle, sum of all angles is 180°, we can find the third angle i.e. ∠DBC.
Thus, ∠DBC = 180°- 90°- 54°
∠DBC = 36°