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2 years ago

F(x) = | sin 3x | -3 find the maximum and minimum value

Mathematics

1 answer:

Reil [10]2 years ago

3 0

Answer:

-2 and -3

Step-by-step explanation:

The minimum of |sin 3x| is 0 and the max is 1 (since the sine function ranges from -1 to 1)

Therefore, the maximum is 1 - 3 = -2 and the minimum is 0 - 3 = -3.

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BARSIC [14]

4. 5x - 4 + 6 - 2s because there is a s unlike the others

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4 0

3 years ago

Read 2 more answers

Can you find the distance from a point to a line?

Naddik [55]

Answer:

5.3 units

Step-by-step explanation:

the height of point p from line MN is 5.3 units

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7 0

4 years ago

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Alberto rode the train 198 miles

Natali5045456 [20]

Answer: Alberto traveled 792 miles as total distance.

Step-by-step explanation:

Since we have given that

Distance rode by the train = 198 miles

Number of times round tip in last month = 4 times

We need to find the total distance that Alberto traveled.

So, Total distance that Alberto traveled is given by

$198\times 4\\\\=792\ miles$

Hence, Alberto traveled 792 miles as total distance.

8 0

4 years ago

Given that phylogenies are based on shared derived characteristics, which of the following traits is useful in generating a phyl

mestny [16]

It seems that you have missed to attach the necessary details for us to answer this given question, so I had to look for it. Anyway, here is the answer. Given that phylogenies are based on shared derived characteristics, the trait that is useful <span>in generating a phylogeny of species w, x, y, and z is TRAIT 2. Hope this helps.</span>

8 0

3 years ago

Let C be the curve of intersection of the parabolic cylinder x^2 = 2y, and the surface 3z = xy. Find the exact length of C from

Maslowich

I've attached a plot of the intersection (highlighted in red) between the parabolic cylinder (orange) and the hyperbolic paraboloid (blue).

The arc length can be computed with a line integral, but first we'll need a parameterization for $C$ . This is easy enough to do. First fix any one variable. For convenience, choose $x$ .

Now, $x^2=2y\implies y=\dfrac{x^2}2$ , and $3z=xy\implies z=\dfrac{x^3}6$ . The intersection is thus parameterized by the vector-valued function

$\mathbf r(x)=\left\langle x,\dfrac{x^2}2,\dfrac{x^3}6\right\rangle$

where $0\le x\le 4$ . The arc length is computed with the integral

$\displaystyle\int_C\mathrm dS=\int_0^4\|\mathbf r'(x)\|\,\mathrm dx=\int_0^4\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}\,\mathrm dx$

Some rewriting:

$\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}=\sqrt{\dfrac{x^2}{36}}\sqrt{x^4+9x^2+36}=\dfrac x6\sqrt{x^4+9x^2+36}$

Complete the square to get

$x^4+9x^2+36=\left(x^2+\dfrac92\right)^2+\dfrac{63}4$

So in the integral, you can substitute $y=x^2+\dfrac92$ to get

$\displaystyle\frac16\int_0^4x\sqrt{\left(x^2+\frac92\right)^2+\frac{63}4}\,\mathrm dx=\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy$

Next substitute $y=\dfrac{\sqrt{63}}2\tan z$ , so that the integral becomes

$\displaystyle\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy=\frac{21}{16}\int_{\arctan(3/\sqrt7)}^{\arctan(41/(3\sqrt7))}\sec^3z\,\mathrm dz$

This is a fairly standard integral (it even has its own Wiki page, if you're not familiar with the derivation):

$\displaystyle\int\sec^3z\,\mathrm dz=\frac12\sec z\tan z+\frac12\ln|\sec x+\tan x|+C$

So the arc length is

$\displaystyle\frac{21}{32}\left(\sec z\tan z+\ln|\sec x+\tan x|\right)\bigg|_{z=\arctan(3/\sqrt7)}^{z=\arctan(41/(3\sqrt7))}=\frac{21}{32}\ln\left(\frac{41+4\sqrt{109}}{21}\right)+\frac{41\sqrt{109}}{24}-\frac98$

4 0

4 years ago