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3 years ago

What is the exact distance from (-4, -2) to (4, 6)? (4 points)

Mathematics

2 answers:

alina1380 [7]3 years ago

7 0

Answer: 12 Units.

Step-by-step explanation: A cornitade gird can help mesure the diffrence in -4 -2 and 4 6

ziro4ka [17]3 years ago

4 0

Answer:

the answer is 12 points

Step-by-step explanation:

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Can someone please help

nexus9112 [7]

Answer:

They are congruent.

Step-by-step explanation:

They both are the same shape and size. The side with one line is the same on the other. The side with two lines also matches the other triangle. Lastly, they both have an angle in the same place

8 0

3 years ago

What the answer to 30-32

kifflom [539]

30. C & D

31. She initially had $30... The cost of each song was $1.20

3 0

3 years ago

What values are solutions to the inequality

vredina [299]

Answer:

Step-by-step explanation:

√x>3

squaring both sides

x>9

so B,C,F

6 0

3 years ago

Read 2 more answers

You have 40 different books (20 math books, 15 history books, and 5 geography books). a. You pick one book at random. What is th

svetoff [14.1K]

Answer:

a. $\frac{3}{8}$

b. $\frac{7}{52}$

c. $\frac{95}{156}$

Step-by-step explanation:

Given,

Total books = 40,

Maths books = 20,

History books = 15,

Geography books = 5,

a. If a book is randomly selected,

Then the probability that the book is a history book,

$=\frac{\text{Ways of choosing history book}}{\text{Ways of choosing any one book}}$

$=\frac{^{15}C_1}{^{40}C_1}$

$=\frac{15}{40}$

$=\frac{3}{8}$

b. If two book is randomly selected,

Then the probability that both books are from history,

$=\frac{\text{Ways of choosing two history book}}{\text{Ways of choosing any two book}}$

$=\frac{^{15}C_2}{^{40}C_2}$

$=\frac{\frac{15!}{2!13!}}{\frac{40!}{2!38!}}$

$=\frac{105}{780}$

$=\frac{7}{52}$

c. If two book is randomly selected,

Ways of selecting any two books from different subjects

= maths and history + maths and geography + history and geography,

$=^{20}C_1\times ^{15}C_1+^{20}C_1\times ^{5}C_1+^{15}C_1\times ^{5}C_1$

$=20\times 15 + 20\times 5 + 15\times 5$

$=300 + 100 + 75$

$=475$

Then the probability that both books are from different subjects

$=\frac{\text{Ways of selecting any two books from different subjects}}{\text{Ways of choosing any two book}}$

$=\frac{475}{780}$

$=\frac{95}{156}$

7 0

3 years ago

What is the 8th term in the sequence? 14, 18, 116, 132, ...

polet [3.4K]

$a_1=14;\ a_2=18\\\\d=a_2-a_1\to d=18-14=4\\\\a_n=a_1+(n-1)d\\\\a_n=14+(n-1)\cdot4=14+4n-4=10+4n\\\\a_8=10+4\cdot4=10+16=36\\\\Answer:\boxed{a_8=36}$

4 0

3 years ago