Answer:
Very little.
Step-by-step explanation:
If you have 1x1=1, and change a number, there is no way that you will get the answer right to be 1.
V ,= 4/3 πr³
solve for r
3V/4=r³
so r is the cubed root of 3V/4
Answer:
- The two solutions are:
![x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B2%7D%2B%2F-%5Cfrac%7B%5Csqrt%7B7%7D%20%7D%7B2%7D)
- The next and every step are below.
Explanation:
1.
: Given (addition property / add - 3 to both sides)
2.
: Given (commom factor - 2)
3. ![-3-1/2=-2(x^2-x+1/4)](https://tex.z-dn.net/?f=-3-1%2F2%3D-2%28x%5E2-x%2B1%2F4%29)
To obtain the perfect square it was added the square of half of the coefficient of x: (1/2)² = 1/4, inside the parenthesis.
Since, the terms inside the parentthesis are multiplied by - 2, you have to add - 2 (1/4) = - 1/2 to the left side of the equation.
4. Now, you have that the trinomial x² - x + 1/4 is a square perfect trinomial which is factored as (x - 1/2)² and get the expression:
![-7/2=-2(x-1/2)^2](https://tex.z-dn.net/?f=-7%2F2%3D-2%28x-1%2F2%29%5E2)
5. Divide both sides by - 2 to get the next expression:
![-7/4=(x-1/2)^2](https://tex.z-dn.net/?f=-7%2F4%3D%28x-1%2F2%29%5E2)
6. The last step is to extract squere root from both sides of the equality:
![(x-1/2)=+/-\sqrt{\frac{7}{4}}\\ \\ x-1/2=+/-\frac{\sqrt{7} }{2}\\ \\ x=\frac{1}{2}+/-\frac{\sqrt{7} }{2}](https://tex.z-dn.net/?f=%28x-1%2F2%29%3D%2B%2F-%5Csqrt%7B%5Cfrac%7B7%7D%7B4%7D%7D%5C%5C%20%5C%5C%20x-1%2F2%3D%2B%2F-%5Cfrac%7B%5Csqrt%7B7%7D%20%7D%7B2%7D%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B1%7D%7B2%7D%2B%2F-%5Cfrac%7B%5Csqrt%7B7%7D%20%7D%7B2%7D)
Answer:
y=-6/5x-2
Step-by-step explanation:
We are given points (5,-8) and (-5,4)
Slope = m = (y₂-y₁)/(x₂-x₁) = (-8-4/(5-(-5)) = -12/10 = -6/5
Y-intercept = b = (0,-2)
Final equation: y=-6/5x-2
Answer:
160 in²
Step-by-step explanation:
20 * 16 / 2
if we wouldn't devide with 2, we would calculate the rectangle around the quadrilateral