We have proven that ΔACO ≅ ΔBDO using the SAS (Side-angle-side) theorem
<h3>Congruent triangles </h3>
From the question, we are to prove that ΔACO ≅ ΔBDO
From one of the congruent triangles theorem, we have that
If <em>two sides</em> and the <em>included angle</em> of one triangle are equal to <em>two sides</em> and the<em> included angle</em> of another triangle, the triangles are congruent.
This is the SAS (Side-angle-side) theorem.
From the given information,
AB and CD intersect at point O
Thus, AO = BO
Also,
∠ACO ≅ ∠BDO
In the diagram, we can as well observe that CO ≅ DO
Thus, we can conclude that AC ≅ BD
Since sides AC, CO and the included angle ACO are <u>congruent</u> to sides BD, DO and the included angle BDO, we can conclude that ΔACO ≅ ΔBDO using the SAS theorem.
Hence, we have proven that ΔACO ≅ ΔBDO
Learn more on Congruent triangles here: brainly.com/question/2938476
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