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2 years ago

What is the solution of |2x+3|< 19

Mathematics

1 answer:

Alex2 years ago

6 0

Answer:

- 11 < x < 8

Step-by-step explanation:

inequalities of the type | x | < a have solutions of the form

- a < x < a

then

| 2x + 3 | < 19

- 19 < 2x + 3 < 19 ( subtract 3 from each interval )

- 22 < 2x < 16 ( divide each interval by 2 )

- 11 < x < 8

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If the dimensions of the following cylinder are doubled, what factor will the surface area change by?

Vedmedyk [2.9K]

Answer:

probably 2 or 4

Step-by-step explanation:

7 0

3 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

Marc has a total of $750 in his account. Every week he withdraws $50 to pay for his weekly expenses. After how many week will he

Sophie [7]

Answer:

after 10 weeks.

Step-by-step explanation:

750 - 50x = 250

-50x = 250 - 750

-50x = -500

x = -500/-50

x = 10

7 0

3 years ago

Read 2 more answers

If f(x) = g(x+1) and g(x) = x^2, find the value of f(3).

Elena-2011 [213]

$\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16$

8 0

4 years ago

F(x)=3x2+1 What is the value of y when x is equal to 0? Hint: f(0)=3(0)2+1

shtirl [24]

7? Let me know if I’m wrong. Have a great day❤️

6 0

3 years ago