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riadik2000 [5.3K]

2 years ago

11

What is the perimeter of JKLM?

1 answer:

Jobisdone [24]2 years ago

5 0

Answer:

45

Step-by-step explanation:

KL = 12 because the triangle is isosceles ( base angles are congruent)

KJ = JM = 12 because the triangle is equilateral ( all angles are equal 60°)

the perimeter is

P = 9 + 12 + 12 +12 = 9 +36 = 45

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Roll two dice what are the chances you roll atleast one six

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3 years ago

If x = 3 is a zero of the polynomial function f(x) = 2x3 + x2 − 25x + 12, which of the following is another zero of f(x)?a. x =

FromTheMoon [43]

Answer:

b) $x=-4$ is another zero of the polynomial

Step-by-step explanation:

Since you are given a set of options to choose from, a very simple way to find the zero of the polynomial is by simply plugging each value from the options and seeing which of them gives the answer 0.

$f(x) = 2x^3+x^2-25x+12\\$

Using all the options:

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Now we know that at x = -4 the value of the polynomial f(x) is 0. hence

b) $x=-4$ is another zero of the polynomial

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Read 2 more answers

Write a quadratic equation with roots of 3/4 and -4

Vaselesa [24]

A quadratic equation given roots is solved by using the relation

${x}^{2} - (sum \: of \: roots)x + product \: of \: roots$

from the question,

sum of the root will be

$\frac{3}{4} + ( - 4) = \frac{3}{4} - 4$

$= \frac{3 - 16}{4}$

$= \frac{ - 13}{4}$

and also, product of the roots will

be

$\frac{3}{4} \times ( - 4) = - 3$

now substituting the sum of roots and product of roots into the equation

${x}^{2} - ( - \frac{13}{4} )x - 3$

$= {x}^{2} + \frac{13}{4} x - 3$

as the quadratic equation for the root 3/4 and -4

4 0

3 years ago

The diagram shows a sector of a circle radius 10cm

Yuki888 [10]

Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

8 0

2 years ago