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2 years ago

mel cuts a slice of cake if her slice is 4/15 of the cake, what is the central angle of her slice, please give answer in degrees

Mathematics

1 answer:

prohojiy [21]2 years ago

7 0

Answer:

Below in bold.

Step-by-step explanation:

That would be 4/15 * 360 as there are 360 degrees in a circle

= 96 degrees.

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A rectangular whiteboard has an area of x^2-12x-45. Which expression could

Firdavs [7]

Answer: I Think it is b

Step-by-step explanation:

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3 years ago

Solve the quadratic equation by completing the square.x^2-14x+46=0First choose the appropriate form and fill in the blanks with

Kaylis [27]

x² - 14x + 46 = 0

subtract 46 from both-side

x² - 14x = -46

Add the square of the half of the co-efficient of x

x² - 14x + (-7)² = -46 + 7²

(x-7)² = -46 + 49

(x-7)² =3

Take the square root of both-side

x-7 = ±√3

x-7= ±1.732

Add 7 to both-side of the equation.

x= 7 ± 1.732

Eithe x= 7 + 1.732 or x= 7 - 1.732

x=8.732 or x=5.268

Therefore x = 8.732 , 5.268

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1 year ago

The ordered pairs (4,5) and (4,-5) are reflected points. Are the locations of these points reflected on the y or the x axis?

My name is Ann [436]

The two coordinates' x variables are the same, while the y variables change. This means that it is reflected over the x axis. Reflecting over the y axis would cause a change in the x variable, as it would have to move sideways, so this can't be the case since the x variable stays as 4 even after the reflection.

8 0

3 years ago

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ANTONII [103]

(x²+4x-12)/(x-2)=0
(x+6)(x-2)/(x-2)=0
x+6=0
x=-6
(-6,0)

8 0

3 years ago

Read 2 more answers