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yaroslaw [1]
2 years ago
5

Step 1: –10 + 8x < 6x – 4

Mathematics
1 answer:
vesna_86 [32]2 years ago
4 0

The final step in solving the inequality is to divide through by -2 and flip the sign

<h3>Solving Inequalities </h3>

From the question, we are to determine the final step in solving the inequality

The given inequality and the steps for solving are

Step 1: –10 + 8x < 6x – 4

Step 2: –10 < –2x – 4

Step 3: –6 < –2x

The final step will be to divide both sides of the inequalities by -2 and then flip the sign

That is,

–6 < –2x

Divide both sides by -2 and flip the sign

3 > x

OR

x < 3

Hence, the final step in solving the inequality is to divide through by -2 and flip the sign

Learn more on Solving inequalities here: brainly.com/question/246993

#SPJ1

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A square with an area of 196 ft2 is reduced by a factor of 1/4. How long the new sides of the square?
soldier1979 [14.2K]

Answer:

49

Step-by-step explanation:

<h2><u>Lesson : Reducing by factors:</u></h2><h2><u /></h2>

Given :

196ft^2

Reduced * factor * of * \frac{1}{4}

When you have to reduce a number by a certain factor, you must divide the area with the amount that it is reducing from, therefore,

\frac{196}{4}

49

5 0
3 years ago
Which value or values would make this equation true? [?]=9
AlexFokin [52]
A. 9 only bc only 9 can be equal to 9 if it was absolutely value then the answer would be 9 and -9
6 0
3 years ago
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for r
butalik [34]

The missing part of the question is show in bold format.

Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it

once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.

You roll it 500 times and get the following data:

Outcome 1 2 3 4 5 6

Frequency 77 92 75 90 76 90

Exercises 1–2

1. If the equality model was correct, about how many of each outcome

would you expect to see if the cube is rolled 500 times

2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?

Answer:

Step-by-step explanation:

1.

If the equally likely model was correct,  about how many of each outcome

would you expect to see if the cube is rolled 500 times.

The probability of rolling any of the numbers from 1 to 6 is  p(1/6)

The number of each of the outcomes expected to be seen in 500 rolls of the number cube is np

= 500 * \frac{1}{6}  \\ \\ = \frac{500}{6} \\ \\  = 83.333 \\ \\ \approx 83

2.  From the given data in the roll;

The odd numbers 1, 3 and 5, were obtained at  77, 75 and 76 times respectively.

Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228

Probability of an odd number turning up = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{228}{500}

= 0.456

= 45.6%

The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.

The total number of times even number were rolled = 92 + 90 + 90 = 272

Probability of an even number turning up  = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{272}{500}

= 0.544

= 54.4%

4 0
3 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
Problem #7 PLEASE HELP ;(
mixer [17]

Answer:

Yes

6(x+0.4) is equivalent to 3(2x+0.8)

Step-by-step explanation:

Given in the questions two expressions

6(x + 0.4)

3(2x + 0.8)

We will apply distributive law

It is a law relating the operations of multiplication and addition, stated symbolically

<h3>a(b + c) = ab + ac</h3><h3 />

6(x + 0.4)

= 6(x) + 6(0.4)

= 6x + 2.4

3(2x + 0.8)

= 3(2x) + 3(0.8)

= 6x + 2.4

Since both equations when expanded have same answers, hence they are equivalent

4 0
3 years ago
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