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ankoles [38]
4 years ago
11

How is the number 5 divisible into 1,620

Mathematics
1 answer:
Gennadij [26K]4 years ago
7 0

-Notice that dividing our numbers leaves no remainder:

1,620 ÷ 5 = 324 + 0

-1,620 has all the factors of the number 5

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The sum of two numbers is 41 and their difference is 5. what are the two numbers
antoniya [11.8K]
This answer is 23 & 18.

Hope this is helpful!
5 0
3 years ago
The number of students in my class went from 25 students to 30 students. What was the percent increase?
Marrrta [24]

Answer:

30/25 - 1 = 0.2 = 20% increase

5 0
3 years ago
Read 2 more answers
Pedro bought lb of red sand and lb of brown sand to refill his sand box. Both types of sand cost $4.60 a pound. How much did Ped
Doss [256]
If we know that Pedro bought 1 \frac{1}{4} pounds of red sand, and 5 \frac{1}{2} pounds of brown sand, and they both cost $4.60, then we just have to add the individual amounts of sand, since they cost the same.

1  \frac{1}{4} + 5  \frac{1}{2} = 6  \frac{3}{4}

So Pedro bought 6 \frac{3}{4} lbs of sand overall. Now, we just need to multiply the cost per pound by the total amount of sand he bought.

6 \frac{3}{4} * 4.6 = 31.05

Pedro spent $31.05 on sand, which is answer choice B.
Hope that helped =)
4 0
3 years ago
Read 2 more answers
Suppose f(x)=x^2. what is the graph of g(x)=1/3 f(x)
saw5 [17]

Step-by-step explanation:

f(x) = x^2

g(x)= 1/3 f(x) = 1/3 x^2

First lets make a table for f(x)= x^2

Lets pick some numbers for x  and find out y

x           y=x^2

-3           (-3)^2 = 9

-1              1

0             0

1              1

3             9

Now we use the same x  values and make a table for g(x)

x         g(x)= \frac{1}{3} x^2

-3          g(x)= \frac{1}{3}(-3)^2=3

-1          g(x)= \frac{1}{3}(-1)^2=\frac{1}{3}

0             0

1           g(x)= \frac{1}{3}(1)^2=\frac{1}{3}

3          g(x)= \frac{1}{3}(3)^2=3

Graph the above table



6 0
3 years ago
a space shuttle is 50 miles above earth an astronaut on the shuttle sees the sun rise over earth. to the nearest mile, what is t
Ludmilka [50]
From the astronaut to the horizon is a tangent line to the curvature of the earth.  And from that point on the horizon to the center of the earth is at a right angle to the tangent and is equal to the radius of the earth...so we can say

cosα=r/(r+h) where r is the radius of the earth and h is the height above the surface of the earth...

α=arccos(r/(r+h))

now tanα=d/r where d is the distance from the astronaut to the point on the horizon so:

tan(arccos(r/(r+h))=d/r

d=rtan(arccos(r/(r+h)))  and using r≈4000 and h=50 we get:

d=4000tan(arccos(4000/(4050)))

d≈634.42mi

d≈634 mi (to nearest mile)
6 0
3 years ago
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