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Marat540 [252]
2 years ago
8

Use the table to the right to answer the following question.

Mathematics
1 answer:
zepelin [54]2 years ago
4 0

The energy is compared based on the information given below.

<h3>How to illustrate the energy?</h3>

Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8

Energy released by fission of hydrogen in 1 kilogram of element B = EB = 1.3 * (10)10

Therefore,

Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25

Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.

Learn more about energy on:

brainly.com/question/13881533

#SPJ1

<u>The other part of the question:</u>

Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8

Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10

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Step-by-step explanation:

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3 years ago
Evaluate the expression. 1/2 - 4 (1/2 + 1)^2
insens350 [35]

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1/2 - 4 (1/2 + 1)^2

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