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Anettt [7]
4 years ago
12

Please help me, this is due in 2 hours!! :-)

Mathematics
1 answer:
erastovalidia [21]4 years ago
6 0
the answer is sieve because seve doesn't have that "I" sound but when you add the letter I to it, it does
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How do you write (x^2)^3 without exponents
Rina8888 [55]
(x^2)^3 is the same as x^6 which is the same as x*x*x*x*x*x
5 0
3 years ago
Please help me with Part B I will give you points and thanks! Thank you
Mumz [18]
2.12=2.120 that is the answer
6 0
3 years ago
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​Yesterday, Grace 42 1/2 drove miles. She used 1 1/4 gallons of gasoline. What is the unit rate for miles per gallon?
Stells [14]

Answer:

34

Step-by-step explanation:

5 0
3 years ago
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What is the sum of two consecutive even integers divided by four is 189.5?
mixas84 [53]
Let us denote the smaller even integer by N.
Then, the next even integer must be N+2.

To verify, set N as any even number, say 174.
Then, the next even integer must be 2 more than this number, i.e. 174+2=176.

The sum of these two consecutive even integers can be expressed as:
                                    N+(N+2)=2N+2

We are told that this sum divided by four is 189.5, i.e.
                                     (2N+2)\div4=189.5

Multiplying both sides by 4 will reverse the division:
     (2N+2)\div4\times4=189.5\times4
     (2N+2)\times1=758

Subtracting 2 from each side will reverse the addition:
     2N+2-2=758-2
     2N=756

Dividing both sides by 2 will reverse the multiplication:
     2N\div2=756\div2
     N=378

Therefore, the two consecutive integers must be 378 and 380.

Check this:
     (378+380)\div4=758\div4=189.5
3 0
3 years ago
Will give Brainly What is the relationship between the sine and cosine of complementary angles in a right triangle? Please give
Lina20 [59]

Answer:

they are equal

Step-by-step explanation:

Consider the right triangle ABC with sides a, b, and c as shown in the figure.  

Let m(\angle A)=\alpha, and m(\angle B)=\beta.

\alpha +\beta=90^{\circ}, so angles A and B are complementary.

According to the definition of sine, and cosine:

\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and

\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}  

4 0
3 years ago
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