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pickupchik [31]
2 years ago
7

Which logarithmic equation correctly rewrites this exponential equation? 8x = 64

Mathematics
1 answer:
ycow [4]2 years ago
6 0

The logarithmic equation of 8^x = 64 is x = \log_8(64)

<h3>How to determine the logarithmic equation?</h3>

The exponential equation is given as:

8^x = 64

Take the logarithm of both sides

xlog(8) = log(64)

Divide both sides by log(8)

x = log(64)/log(8)

Apply the change of base rule

x = \log_8(64)

Hence, the logarithmic equation of 8^x = 64 is x = \log_8(64)

Read more about logarithmic equation at:

brainly.com/question/3181916

#SPJ1

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What is the equation, in slope-intercept form, of the line
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<u>Given</u>:

Given that the graph of the equation of the line.

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The slope of the given line can be determined by substituting any two coordinates from the line in the slope formula,

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m_1=\frac{2-3}{2+1}

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<u>Slope of the perpendicular line:</u>

The slope of the perpendicular line can be determined by

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m_2=-\frac{1}{-\frac{1}{3}}

simplifying, we get;

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<u>Equation of the perpendicular line:</u>

The equation of the perpendicular line can be determined using the formula,

y-y_1=m(x-x_1)

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Thus, the equation of the perpendicular line is y=3x-7

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Answer:

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