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ella [17]
3 years ago
5

How do you do this please explain

Mathematics
1 answer:
MArishka [77]3 years ago
6 0
What is the lesson? We are aware that the 2 triangles are congruent, they also tell us what the two segments are equal to. Your best is to set up an equation making the segments equal to eachother to find the value of segment WK
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What percent of 70 is 28?
Mumz [18]

Answer: 40%

Step-by-step explanation:

This represents this equation:

70*x =28

x=28/70=0,4

Multiply that with 100 to get the percentage.

5 0
3 years ago
Read 2 more answers
Information about five planets is shown in the table below.
Karo-lina-s [1.5K]

Answer:

(a)Jupiter

(b)24.4 km

(c)1.33 \times 10^{27}$ kg

Step-by-step explanation:

<u>Part A</u>

The planet with the greatest ma.ss is Jupiter.

It has a ma.ss of 1.898 X 10^{27}$ kg

<u>Part B</u>

The diameter of Mercury = 4.88 X 10

Radius = Diameter/2

Therefore:

Radius of Mercury

=\dfrac{4.88 X 10}{2}\\ =2.44 X 10\\=24.4$ km

<u>Part C</u>

M$a.ss of Saturn = 5.68 X 10^{26}\\$Mass of Jupiter = 1.898 X 10^{27}\\$Difference in their ma.ss =(1.898 X 10^{27})-(5.68 X 10^{26})\\=1.33 \times 10^{27}$ kg

4 0
3 years ago
Evaluate: ab – bc if a = 4, b = 3, and c = 2
Juli2301 [7.4K]

Answer:

6

ab-cd

Substitute the values in the equation

(4)(3)-(3)(2)

12-6=6

8 0
3 years ago
Factor this expression completely 9x^2- y^2
Nina [5.8K]

Answer:

(3x - y)(3x + y)

Step-by-step explanation:

Both 9x^2 and y^2 are perfects squares.

The rule for factoring perfect squares is a^2 - b^2 = (a - b)(a + b).

Here, factoring (3x)^2 - y^2 results in (3x - y)(3x + y).

7 0
3 years ago
Read 2 more answers
Someone help me with this
Jet001 [13]

2a. 14,9; 2b. 15,4; 2c. 30,8; 3. 32

For 2a., you have to set it up like this: csc 48° = 20⁄x [OR sin 48° = ˣ⁄20]. Then you would have to isolate the variable by getting rid of the denominator. The cosecant function has an extra step because you will get xcsc 48° = 20. As stated, isolate the variable; this time, divide by csc 48°. This is what 20 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2b., you have to set it up like this: sec 39° = ˣ⁄12 [OR cos 39° = 12⁄x. Then you would have to isolate the variable by getting rid of the denominator. The cosine function has an extra step because you will get xcos 39° = 12. As stated, isolate the variable; this time, divide by cos 39°. This is what 12 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2c., you have to set it up like this: cot 64° = 15⁄x [OR tan 64° = ˣ⁄15]. Then you would have to isolate the variable by getting rid of the denominator. The cotangent function has an extra step because you will get xcot 64° = 15. As stated, isolate the variable; this time, divide by cot 64°. This is what 15 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

Now, for 3., it is unique, but similar concept. In this exercise, we are solving for an angle measure, so we have to use inverse trigonometric ratios. So, we set it up like this: cot⁻¹ 1⅗ = m<x [OR tan⁻¹ ⅝ = m<x]. We simply input this into our calculator and we get 32,00538321°. When rounded to the nearest degree, we get 32°.

WARNING: If you use a graphing calculator, you have to input it uniquely because most graphing calculators do not have the inverse trigonometric ratios programmed in their systems. This is how you would write this: tan⁻¹ 1⅗⁻¹. You set 1⅗ to the negative first power, ALONG WITH the inverse tangent function, because without it, your answer will be thrown off. Since Cotangent and Tangent are multiplicative inverses of each other, that is the reason why the negative first power is applied ALONG WITH the inverse tangent function.

**NOTE: 1⅗ = 8⁄5

Take into consideration:

sin <em>θ</em> = O\H

cos <em>θ</em><em> </em>=<em> </em>A\H

tan <em>θ</em><em> </em>= O\A

sec <em>θ</em><em> </em>= H\A

csc <em>θ</em><em> </em>= H\O

cot <em>θ</em><em> </em>= A\O

I hope this helps you out alot, but if you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
3 years ago
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