Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
15% of 40
Of = Multiplication
15% Multiply by 40
Set up a equation
15/100= x/140
Cross Multiply
15* 140= 100*x
2100= 100x
Divide both sides by 100x
2100/100x= 100x/100x
X= 21
Answer:

Step-by-step explanation:
Given


Required
The distance between the top and John
The distance is calculated using:

Where
--- the angle between the diagonal line and the vertical line


So, we have:






<em> --- approximated</em>
Answer:
The first statement is correct
Step-by-step explanation:
0.654 < 0.674 is correct because 0 is the same, 6 is the same, but 7 is larger than 5.