All categories

2 years ago

What is the ratio of my lawn if it is 4 meters by 4.5 meters

Mathematics

1 answer:

sammy [17]2 years ago

7 0

Answer:

The 1:n ratio is= 1 : 1.125

The n:1 ratio is= 8/9 : 1

Just the simple ratio is= 4 : 4.5

You might be interested in

115. Sami opens an account and deposits $100 into it at the end of each month. The account earns 2% per year compounded monthly.

givi [52]

Step-by-step explanation:

Geometric series.

Month 3.

100(1+\frac{0.02}{12})^2 + 100(1+\frac{0.02}{12})+100

Month 4.

100( 1 + \frac{0.02}{12})^3 + 100( 1 + \frac{0.02}{12})^2+100(1+\frac{0.02}{12})+100

Month 5.

100(1 + \frac{0.02}{12})^4 + 100(1 + \frac{0.02}{12})^3 + 100(1 + \frac{0.02}{12})^2 +100( 1 + \frac{0.02}{12}) + 100

4 0

4 years ago

Plzzzzzz someone help I keep on getting a decimal answer that is 100% wrong. Please do number 14

ANEK [815]

Im sorry number 14 of what?

6 0

3 years ago

Which expression will help you find the area of the triangular bases?

AnnZ [28]

Answer:

The correct answer is 1/2×8×3.

3 0

3 years ago

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: "the cost of working for 100 hours is $130000"

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

(a) Functions c(n) and n(h)

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

(b) Function c(n(h))

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

(c) Find c(n(100))

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

(d) Interpret (c)

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

At midnight, the temperature was 34°F. By 6:00 a.m. it had dropped 8°, and by noon it had increased by 11°. What was the tempera

olga_2 [115]

Answer:

The temperature at noon was 37 °F.

Step-by-step explanation:

Given:

Temperature at midnight is 34 °F.

Reduction in temperature by 6:00 a.m. is 8°. So, temperature after reduction is given as the difference in temperature at midnight and morning.

Therefore, temperature by 6:00 a.m. in the morning is given as:

Reduced temperature = Midnight temperature - Reduction in temperature.

Reduced temperature = 34 °F - 8 °F = 26 °F.

Now, by noon, the temperature is increased by 11 °F. Therefore, the final temperature by noon is addition of 11 degree to the temperature that was in the morning. Therefore,

Temperature at noon = Temperature in morning + Increase in temperature.

Temperature at noon = 26 °F + 11 °F = 37 °F.

So, the temperature at noon is a 3 °F increase to the temperature at midnight and is equal to 37 °F.

7 0

3 years ago