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gayaneshka [121]
1 year ago
7

Graph the line Y=2/5X+5

Mathematics
1 answer:
Charra [1.4K]1 year ago
4 0
Here is your answer to this question.

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I need help please #19
o-na [289]

Answer:

40

Step-by-step explanation:

5 0
3 years ago
A,D,N, and X are collinear points. D is between N and A. NA+AX=NX. Draw a diagram that represents this information. Help!!!
GREYUIT [131]
I hope this helps you out!

3 0
3 years ago
Write a cubic function whose graph goes through the points: (-5, 0) (1, 0) (2, -2) (4, 0)
Free_Kalibri [48]

Answer:

f(x) = \frac{1}{7}(x+5)(x-1)(x-4)

Step-by-step explanation:

Let the equation of the give cubic function is,

f(x) = p(x - a)(x - b)(x - c)

Here, a, b, c and d are the x-intercepts of the given graph.

Since, x-intercepts given in the graph are x = -5, 1 and 4,

Equation of the curve will be,

f(x) = p(x + 5)(x - 1)(x - 4)

Since, the graph of this function passes through (2, -2) also

-2 = p(2 + 5)(2 - 1)(2 - 4)

-2 = -p(14)

p = \frac{2}{14}

p = \frac{1}{7}

Therefore, equation will be,

f(x) = \frac{1}{7}(x+5)(x-1)(x-4)

5 0
3 years ago
A research engineer for a tire manufacturer is investigating tire life for a new rubber compound and has built 16 tires and test
frutty [35]

Answer:

The 95% confidence interval for mean tire life is between 52,368.4 kilometers and 67,911 kilometers.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 15 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.68

The margin of error is:

M = T*s = 2.1315*3645.94 = 7771.3

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60139.7 - 7771.3 = 52,368.4.

The upper end of the interval is the sample mean added to M. So it is 60139.7 + 7771.3 = 67,911.

The 95% confidence interval for mean tire life is between 52,368.4 kilometers and 67,911 kilometers.

3 0
3 years ago
Read 2 more answers
A telephone pole broke 4 feet from the bottom. If the top of the pole landed 3 feet from the base of the tree, how tall was the
SIZIF [17.4K]
The answer is the squared root of 7
3 0
3 years ago
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