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PtichkaEL [24]
3 years ago
11

A regular hexagonal prism has a volume of 160 cubic meters. Its base has a perimeter of 30 meters and an area of 64 square meter

s. What is the surface area, in square meters, of the hexagonal prism?
Mathematics
1 answer:
valkas [14]3 years ago
5 0
We know that

[volume of a <span>regular hexagonal prism]=[area of the base]*height
height=volume/area of the base
h=160/64-----> 2.5 m

[surface area </span><span>hexagonal prism]=2*[area of the base]+[perimeter of base]*h
</span>[surface area hexagonal prism]=2*[64]+[30]*2.5----> 203 m²

the answer is
203 m²
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33/4

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Nancy found that x=1 is one solution to the quadratic equation (x 2)2=a. what is the value of a? -9 -3 3 9
AlladinOne [14]

The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.

<h3>What is the solution of equation?</h3>

The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.

Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,

(x +2)^2=a

For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>

(1 +2)^2=a\\(3)^2=a\\9=a\\a=9

Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.

Learn more about the solution of the equation here;

brainly.com/question/21283540

5 0
2 years ago
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In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi
chubhunter [2.5K]

Answer:

The length of b is \sqrt{2x^2(1-cos\beta)}.

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

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According to Law of cosine

b^2=a^2+c^2-2ac\cos B

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b^2=2x^2-2x^2\cos \beta

b^2=2x^2(1-\cos \beta)

\sqrt{2x^2(1-cos\beta)}

Therefore the length of b is \sqrt{2x^2(1-cos\beta)}.

6 0
3 years ago
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