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NeX [460]
3 years ago
9

State whether the value for the unknown makes inequalities 74/e < 12

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

74/e < 12

Since e is in the denominator, e can not be 0.

If e > 0,

74/e < 12

74 < 12e

e > 74/12

e < 37/6

If e < 0,

(When you multiply by e, which is a negative value, inequality reverses)

74 > 12e

e < 74/12

e < 37/6

soldi70 [24.7K]3 years ago
6 0

Answer:

37/6 < e or e<0

Step-by-step explanation:

74/e < 12

Multiply each side by e

74/e *e < 12*e

74 <12e

Divide each side by 12

74/12 <12e/12

37/6 < e

If e is less than 0, the inequality will flip

74/e *e > 12*e

Divide each side by 12

74/12 >12e/12

37/6 > e

But we limited it to less than 0

0 >e

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Given A = {x | x &lt; 1}, B = {x | x ≥ 5}, and C = {x | x = 5}, match the following items. 1. A B Ø 2. A C {x | x ≥ 5} 3. B C {x
ivann1987 [24]

Answer:

The matching is shown below.

Step-by-step explanation:

The given sets are defined as

A = {x | x < 1}

It means all the values of x which are less than 1.

B = {x | x ≥ 5}

It means all the values of x which are greater than or equal to 5.

C = {x | x = 5}

It means all the value of x is 5.

Union of two sets contains all the elements of both sets.

Intersection of two sets contains only common elements of both sets.

The matching is shown below.

        Sets                              Correct value

1.     A ∪ B                         {x | x < 1 or x ≥ 5}

2. A ∪ C                         {x | x < 1 or x = 5}

3. B ∪ C                         {x | x ≥ 5}

4. A ∩ B                         Ø

5. B ∩ C                         {x | x = 5}

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The sum of three numbers $x$ ,$y$, $z$ is 165. When the smallest number $x$ is multiplied by 7, the result is $n$. The value $n$
babymother [125]

You're given

<em>x</em> + <em>y</em> + <em>z</em> = 165

7<em>x</em> = <em>n</em>

<em>n</em> = <em>y</em> - 9

<em>n</em> = 9 + <em>z</em>

and you want to find <em>xyz</em>.

Solve the last three equations for <em>x</em>, <em>y</em>, and <em>z</em> :

7<em>x</em> = <em>n</em>   →   <em>x</em> = <em>n</em>/7

<em>n</em> = <em>y</em> - 9   →   <em>y</em> = <em>n</em> + 9

<em>n</em> = 9 + <em>z</em>   →   <em>z</em> = <em>n</em> - 9

Substitute <em>x</em>, <em>y</em>, and <em>z</em> into the first equation and solve for <em>n</em> :

<em>n</em>/7 + (<em>n</em> + 9) + (<em>n</em> - 9) = 165

<em>n</em>/7 + 2<em>n</em> = 165

<em>n</em> + 14<em>n</em> = 1155

15<em>n</em> = 1155

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Now solve for <em>x</em>, <em>y</em>, and <em>z</em> :

<em>x</em> = 77/7 = 11

<em>y</em> = 77 + 9 = 86

<em>z</em> = 77 - 9 = 68

Then the product is

<em>xyz</em> = 11 • 86 • 68 = 64,328

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Answer:

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Step-by-step explanation:

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