<em>Answer:</em>
<em />
<em>x³ + x² - 6x = 0</em>
<em>x(x² + x - 6) = 0</em>
<em>x(x² + 3x - 2x - 6) = 0</em>
<em>x[x(x + 3) - 2(x + 3)] = 0</em>
<em>x(x - 2)(x + 3) = 0</em>
<em>x₁ = 0</em>
<em>x - 2 = 0 => x₂ = 2</em>
<em>x + 3 = 0 => x₃ = - 3</em>
Answer:
d
Step-by-step explanation:
Answer:
no solution
Step-by-step explanation:
sqrt(3x+1) +7 = 5
Subtract 7 from each side
sqrt(3x+1) +7 -7= 5-7
sqrt(3x+1) = -2
The sqrt cannot be negative so there is no solution
Step-by-step explanation:
substitute 2 into x
1. (u ○ w)(2)
u(w(x))
= 4(-5x+1)+2
= 4(-5.2+1)+2
= 4(-9)+2
=-34
2. (w ○ u)(2)
w(u(x))
= -5(4x+2)+1
= -5(4.2+2)+1
= -5(10)+1
= -49
