Let's plug in x = 2.
f(x) = x^2
f(2) = 2^2 ... replace every x with 2
f(2) = 4
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Now plug in x = 3.
f(x) = x^2
f(3) = 3^2 ... replace every x with 3
f(3) = 9
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And x = 5 as well.
f(x) = x^2
f(5) = 5^2 .... replace every x with 5
f(5) = 25
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We see that
f(2)+f(3) = 4+9 = 13
which is not equal to f(5) = 25.
So f(2)+f(3) = f(5) is false.
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Another way to phrase why it doesn't work is because (2,3,5) isn't a pythagorean triple. The equation 2^2+3^2 = 5^2 is false.
If it said f(3)+f(4) = f(5), then it would be correct because 3^2+4^2 = 5^2 is a true equation.
Answer:
i need more information
Step-by-step explanation:
Answer=20,000
16,500 is greater than 15,000, so you would round up to 20,000
What arc QR?
Is there supposed to be a picture here?
Answer:
Step-by-step explanation:
hello :
put n=32 A32 = 12 +(32-1)3 =105
