Hey!
Let p = cost of a pen
<span>Let n = cost of a notebook </span>
<span>The info in the question leads to two equations: </span>
<span>1) 2p + 3n = 5.55 </span>
<span>2) p + 2n = 3.50 </span>
<span>Multiply equation 2) by 2 to get the new system of equations </span>
<span>1a) 2p + 3n = 5.55 </span>
<span>2a) 2p + 4n = 7.00 </span>
<span>Subtract equation 1a) from equation 2a) to get </span>
<span>n = 1.45 ...................... that's the cost of one notebook </span>
<span>~~~~~~~~ </span>
<span>To check, you could go on to figure out p, which turns out to be 0.60 . Put in those values of n and p into the original equations to verify.</span>
Hope this helps! ~Nadia~
First, plug in -3 for the y value.
-3=2x²-10x
Then, add 3 to both sides.
0=2x²-10x+3
Use the quadratic equation to solve
(-b+-√b²-4ac)/2a
You get 4.68 or 0.32
You still have to check your answer to see if there is an excluded value.
Both values check.
Answer:
B
Step-by-step explanation:
For a polynomial , the behaviour as x gets large is determined by the term of greatest degree,
f(x) = - 2
- x³ + 3
Is of even degree with a negative leading coefficient , then
f(x) → - ∞ as x → + ∞ and f(x) → - ∞ as x → - ∞

Here , the given data is :
- Principal = Rs 4400 . ( P )
- Time = 3 years . ( T )
- Rate of Internet = 8% . ( R )
We can calculate Simple Interest using ,

On substituting the respective values ,
⇒ SI = P × R × T / 100.
⇒ SI = Rs 4400 × 8 × 3 / 100 .
⇒ SI = Rs 44 × 8 × 3 .
⇒ SI = Rs 1,056 .
<u>Hence</u><u> </u><u>the</u><u> </u><u>requ</u><u>ired</u><u> </u><u>Interest</u><u> </u><u>is</u><u> </u><u>Rs</u><u> </u><u>1</u><u>,</u><u>0</u><u>5</u><u>6</u><u>.</u>
Answer:
b
Step-by-step explanation:
im in the 12 grade
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