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2 years ago

Point A is at (3, -8) and point B is at (7, 3). Point M is the midpoint of point A and point B.

Mathematics

1 answer:

IgorC [24]2 years ago

7 0

The midpoint of point A and point B is (5, -2.5)

<h3>How to determine the midpoint?</h3>

The coordinates are given as:

A = (3, -8)

B = (7, -3)

The midpoint is calculated as:

(x, y) = 0.5 * (x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 * (3 + 7, -8 + 3)

This gives

(x, y) = 0.5 * (10, -5)

Evaluate

(x, y) = (5, -2.5)

Hence, the midpoint of point A and point B is (5, -2.5)

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This figure consist of a rectangle a semi circle and a quarter circle what is the perimeter of this figure use 3.14 for pi

alexandr402 [8]

Answer:

37.55 m

Step-by-step explanation:

To find the perimeter, we have to add the lengths of each part of the figure.

We start from the circle on top. We see that its diameter is 10 m, therefore its radius is

r = 5 m

(because the radius is half the diameter). The perimeter of a circle is given by

$p=2 \pi r$

However, here we have half a circle, so its perimeter is

$p_1 = \pi r=(3.14)(5)=15.7 m$

Then continuing in a clockwise direction, we have to add the length of the side of 2 m:

$p_2 = 2 m$

Then we have two sides of a square of side 5 m, so:

$p_3 = 5 m + 5 m= 10 m$

Then we have a quarter of a circle of radius r = 5 m, so its perimeter is:

$p_4 = \frac{\pi r}{2}=\frac{\pi (5)}{2}=7.85 m$

Finally, we have one more side of length 2 m:

$p_5 = 2m$

Therefore, the total perimeter is:

$p=p_1+p_2+p_3+p_4+p_5=15.7+2+10+7.85+2=37.55 m$

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Vcylinder=hpir^2
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