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Fittoniya [83]
3 years ago
12

Which table has a constant of proportionality between y and x of 8/5

Mathematics
1 answer:
Fantom [35]3 years ago
3 0

Answer:

A.) is my best guess

Step-by-step explanation:

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the birth rate in a certain country in 1994 was 14,6 birthd per thousand population. in 2004 the birth rate was 14.32 per thousa
amm1812

Answer:

y(x)=-0.028x+14.6

Step-by-step explanation:

Birth Rate in 1994 =  14.6 births per thousand population.

Birth Rate in 2004 =  14.32 births per thousand population.

A linear equation is of the form: y=mx+c

Where:

  • x=years after 1994
  • y=the birth rate
  • m=Yearly Birth Rate

First, we determine the birth rate per year

m=\dfrac{14.32-14.6}{10-0}\\=\dfrac{-0.28}{10}\\m=-0.028

Therefore, a linear equation that relates y in terms of x is of the form:

y(x)=-0.028x+c

When x=0, y=14.6

14.6=-0.028(0)+c

c=14.6

Therefore, the linear equation that relates y in terms of x is:

y(x)=-0.028x+14.6

4 0
3 years ago
Derrick really wants to earn at least $330 at the Bike Shop. He earns $150 per week plus $15.50 for each bicycle that he assembl
MA_775_DIABLO [31]

Answer: He will need to assemble 12 bikes, because 12 x 15.50 = $186 and $186 + 150 = $336

Step-by-step explanation: Don't need one :)) it's basic math

8 0
3 years ago
Read 2 more answers
Bob raises Guinea Pigs and Chinchillas on his beachfront oasis. There are a total of 60,005 animals at the oasis. The number of
raketka [301]
Let named variables as you said g- guinea pigs and c- chinchillas
System of equation is:

First is:   c+ g = 60,005 
Second is:   c= 2g+5

When we replace second in first we get:

2g+5+g = 60,005 => 3g+5= 60,005 => 3g= 60,000

g=60.000/3 = 20,000 => g=20,000

When this result we replace in the second equation we get

c= 2 * 20,000 +5= 40,000+5 = 40,005

c= 40,005

Good luck!!!!




6 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

                     L + W = 10

                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
Giving brainiest
mestny [16]

Answer:

7x2 is 14

I will adopt you

Step-by-step explanation:

5 0
3 years ago
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