Question

Suppose the probability that a Wide Receiver catches a ball thrown to him is 0.9. Let X model the number of catches he has if he is targeted 8 times in a game. What is the mean number of balls you would expect him to catch

Answer 1

Using the binomial distribution, the mean number of balls you would expect him to catch is of 7.2.

What is the binomial probability distribution?

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

For this problem, the parameters are:

n = 8, p = 0.9.

Hence the mean is:

E(X) = np = 8 x 0.9 = 7.2.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1