The dimensions of the pool is 15m by10m
<h3>Area and perimeter of rectangle</h3>
A pool is rectangular in nature. If a rectangular swimming pool has an area of 150 square meters and a perimeter of 50 meters, then;
lw = 150
2(l+w) = 50
l + w = 25
where
l is the length
w is the width
From the equation 3
l = 25 - w
Substitute into 1
(25-w)w = 150
25w-w² = 150
w²-25w+150 = 0
w²-10w-15w+150 = 0
Factor
w(w-10)-15(w-10) = 0
w = 10 and 15
l = 150/10 = 15
Hence the dimensions of the pool is 15m by10m
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Well threw my calculations would be <span><span> x= 0.0000 - 2.0000 i
</span><span> x= 0.0000 + 2.0000 i
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Answer:
True!
Step-by-step explanation:
9514 1404 393
Answer:
$7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
p + d + q = 45 . . . . . . . . there are 45 coins in the collection
2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
p +(p +4) +(2p +5) = 45
4p = 36 . . . . . . . . . . . . . subtract 9
p = 9 . . . . . . . . . . . divide by 4
d = 9 +4 = 13
q = 2(9) +5 = 23
The value of the collection is ...
23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.